แก้โจทย์ {l}{y+x+z=6}{x^2=3y+2z}

$$\left. \begin{array} { l } { y + x + z = 6 } \\ { x ^ { 2 } = 3 y + 2 z } \end{array} \right.$$

หาค่า x, y, z (complex solution)

$$x=6-z-y\text{, }y=-z+\frac{\sqrt{81-4z}}{2}+\frac{15}{2}\text{, }z\in \mathrm{C}$$

$$x=6-z-y\text{, }y=-z-\frac{\sqrt{81-4z}}{2}+\frac{15}{2}\text{, }z\in \mathrm{C}$$

หาค่า x, y, z

$$x=6-z-y\text{, }y=-z+\frac{\sqrt{81-4z}}{2}+\frac{15}{2}\text{, }z\leq \frac{81}{4}$$

$$x=6-z-y\text{, }y=-z-\frac{\sqrt{81-4z}}{2}+\frac{15}{2}\text{, }z\leq \frac{81}{4}$$