Решить 8xgeq20 | Microsoft Math Solver

Решение для x

x \geq \frac{5}{2}

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Algebra

8 x \geq 20

Подобные задачи из результатов поиска в Интернете

How do you graph

- x \geq 20

on the coordinate plane?

https://socratic.org/questions/how-do-you-graph-x-20-on-the-coordinate-plane

See a solution process below: Explanation: First solve for

x

by multiplying each side of the inequality by

(- 1)

. However, because we are ...

Determine the lowest value of

A

such that

f (x) \geq 20

for all

x > 0

https://math.stackexchange.com/questions/2896659/determine-the-lowest-value-of-a-such-that-f-x-geq20-for-all-x-0

You can use the A.M. G.M. method because here

x^{3}

and

\frac{A}{x ^{3}}

are positive.

\frac{3 x ^{3} + \frac{A}{x ^{3}}}{2} \geq (3 A)^{\frac{1}{2}}

3 x^{3} + \frac{A}{x ^{3}} \geq 2 (3 A)^{\frac{1}{2}}

...

How do you solve and graph

x - 1 \leq 9

2 x \geq 24

https://socratic.org/questions/how-do-you-solve-and-graph-x-1-9-or-2x-24

Mark D. Jun 25, 2018 Take

x - 1 \leq 9

add 1

x \leq 10

Now look at

2 x \geq 24

divide by2

x \geq 12

...

f (1) = 10

and

f ’ (x) \geq 2

for

1 \leq x \leq 4

, how small can

f (4)

possibly be?

https://www.quora.com/If-f-1-10-and-f-x-geq-2-for-1-leq-x-leq-4-how-small-can-f-4-possibly-be

Think it in very simple way. What is slope of the function? Slope is the change in the value of the function per unit change in the value of the x value. f(x) is an increasing function with minimum ...

Looking for help in understanding Jitsuro Nagura's analysis of the upper bound for

ψ (x)

https://math.stackexchange.com/q/378642

A second application of the inequality

ψ (x) < 1.0851 x + ψ (\frac{x}{1 8 0 6})

gives

ψ (x) < 1.0851 x (1 + \frac{1}{1 8 0 6}) + ψ (\frac{x}{1 8 0 6 ^{2}})

In general, ...

what does it mean to reject a hypothesis?

https://math.stackexchange.com/questions/2863519/what-does-it-mean-to-reject-a-hypothesis

5 - 2 x \geq 0 ⟺ ∣ 5 - 2 x ∣ = 5 - 2 x

but

5 - 2 x \geq 0 ⟺ 2 x \leq 5,

unlike what you wrote. In this particular exercise, no hypothesis is rejected, so it doesn't illustrate the concept.

Скопировано в буфер обмена

x\geq \frac{20}{8}

Разделите обе части на 8. Так как 8 является положительным, неравенство будет совпадать.

x\geq \frac{5}{2}

Привести дробь \frac{20}{8} к несократимому виду, разделив числитель и знаменатель на 4.

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