Решить {l}{G={(x-1)}{(x+4)}+{(x-1)}{(x+5)}}{c=b+4a^2}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { G = {(x - 1)} {(x + 4)} + {(x - 1)} {(x + 5)} }\\ { c = b + 4 a ^ {2} }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Найдите x (комплексное решение)

$$x=\frac{-\sqrt{8G+121}-7}{4}$$

$$x=\frac{\sqrt{8G+121}-7}{4}\text{, }b=d-4a^{2}\text{ and }c=4a^{2}+b$$

Найдите x

$$x=\frac{-\sqrt{8G+121}-7}{4}$$

$$x=\frac{\sqrt{8G+121}-7}{4}\text{, }b=d-4a^{2}\text{ and }G\geq -\frac{121}{8}\text{ and }c=4a^{2}+b$$