Solve for y
y=\frac{z}{3}
Solve for z
z=3y
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-3y=-z
Subtract z from both sides. Anything subtracted from zero gives its negation.
\frac{-3y}{-3}=-\frac{z}{-3}
Divide both sides by -3.
y=-\frac{z}{-3}
Dividing by -3 undoes the multiplication by -3.
y=\frac{z}{3}
Divide -z by -3.
z=3y
Add 3y to both sides. Anything plus zero gives itself.
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