4, sine, theta, cosine, theta, equals, 2, sine, theta

Solve for θ

\theta =2\pi n_{2}+\frac{\pi }{3}\text{, }n_{2}\in \mathrm{Z}

\theta =2\pi n_{3}+\frac{5\pi }{3}\text{, }n_{3}\in \mathrm{Z}

\theta =\pi n_{1}\text{, }n_{1}\in \mathrm{Z}

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