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z^{2}-z+0.368+0.264=0
Combine -1.386z and 0.386z to get -z.
z^{2}-z+0.632=0
Add 0.368 and 0.264 to get 0.632.
z=\frac{-\left(-1\right)±\sqrt{1-4\times 0.632}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -1 for b, and 0.632 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
z=\frac{-\left(-1\right)±\sqrt{1-2.528}}{2}
Multiply -4 times 0.632.
z=\frac{-\left(-1\right)±\sqrt{-1.528}}{2}
Add 1 to -2.528.
z=\frac{-\left(-1\right)±\frac{\sqrt{955}i}{25}}{2}
Take the square root of -1.528.
z=\frac{1±\frac{\sqrt{955}i}{25}}{2}
The opposite of -1 is 1.
z=\frac{\frac{\sqrt{955}i}{25}+1}{2}
Now solve the equation z=\frac{1±\frac{\sqrt{955}i}{25}}{2} when ± is plus. Add 1 to \frac{i\sqrt{955}}{25}.
z=\frac{\sqrt{955}i}{50}+\frac{1}{2}
Divide 1+\frac{i\sqrt{955}}{25} by 2.
z=\frac{-\frac{\sqrt{955}i}{25}+1}{2}
Now solve the equation z=\frac{1±\frac{\sqrt{955}i}{25}}{2} when ± is minus. Subtract \frac{i\sqrt{955}}{25} from 1.
z=-\frac{\sqrt{955}i}{50}+\frac{1}{2}
Divide 1-\frac{i\sqrt{955}}{25} by 2.
z=\frac{\sqrt{955}i}{50}+\frac{1}{2} z=-\frac{\sqrt{955}i}{50}+\frac{1}{2}
The equation is now solved.
z^{2}-z+0.368+0.264=0
Combine -1.386z and 0.386z to get -z.
z^{2}-z+0.632=0
Add 0.368 and 0.264 to get 0.632.
z^{2}-z=-0.632
Subtract 0.632 from both sides. Anything subtracted from zero gives its negation.
z^{2}-z+\left(-\frac{1}{2}\right)^{2}=-0.632+\left(-\frac{1}{2}\right)^{2}
Divide -1, the coefficient of the x term, by 2 to get -\frac{1}{2}. Then add the square of -\frac{1}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
z^{2}-z+\frac{1}{4}=-0.632+\frac{1}{4}
Square -\frac{1}{2} by squaring both the numerator and the denominator of the fraction.
z^{2}-z+\frac{1}{4}=-\frac{191}{500}
Add -0.632 to \frac{1}{4} by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.
\left(z-\frac{1}{2}\right)^{2}=-\frac{191}{500}
Factor z^{2}-z+\frac{1}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(z-\frac{1}{2}\right)^{2}}=\sqrt{-\frac{191}{500}}
Take the square root of both sides of the equation.
z-\frac{1}{2}=\frac{\sqrt{955}i}{50} z-\frac{1}{2}=-\frac{\sqrt{955}i}{50}
Simplify.
z=\frac{\sqrt{955}i}{50}+\frac{1}{2} z=-\frac{\sqrt{955}i}{50}+\frac{1}{2}
Add \frac{1}{2} to both sides of the equation.