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z\left(z+36\right)=0
Factor out z.
z=0 z=-36
To find equation solutions, solve z=0 and z+36=0.
z^{2}+36z=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
z=\frac{-36±\sqrt{36^{2}}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 36 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
z=\frac{-36±36}{2}
Take the square root of 36^{2}.
z=\frac{0}{2}
Now solve the equation z=\frac{-36±36}{2} when ± is plus. Add -36 to 36.
z=0
Divide 0 by 2.
z=-\frac{72}{2}
Now solve the equation z=\frac{-36±36}{2} when ± is minus. Subtract 36 from -36.
z=-36
Divide -72 by 2.
z=0 z=-36
The equation is now solved.
z^{2}+36z=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
z^{2}+36z+18^{2}=18^{2}
Divide 36, the coefficient of the x term, by 2 to get 18. Then add the square of 18 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
z^{2}+36z+324=324
Square 18.
\left(z+18\right)^{2}=324
Factor z^{2}+36z+324. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(z+18\right)^{2}}=\sqrt{324}
Take the square root of both sides of the equation.
z+18=18 z+18=-18
Simplify.
z=0 z=-36
Subtract 18 from both sides of the equation.