Solve for y
y=\frac{x^{2}-z}{3}
Solve for x
x=\sqrt{3y+z}
x=-\sqrt{3y+z}\text{, }z\geq -3y
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x^{2}-3y=z
Swap sides so that all variable terms are on the left hand side.
-3y=z-x^{2}
Subtract x^{2} from both sides.
\frac{-3y}{-3}=\frac{z-x^{2}}{-3}
Divide both sides by -3.
y=\frac{z-x^{2}}{-3}
Dividing by -3 undoes the multiplication by -3.
y=\frac{x^{2}-z}{3}
Divide z-x^{2} by -3.
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