Solve for x
\left\{\begin{matrix}x=-\frac{1-z}{2y}\text{, }&y\neq 0\\x\in \mathrm{R}\text{, }&z=1\text{ and }y=0\end{matrix}\right.
Solve for y
\left\{\begin{matrix}y=-\frac{1-z}{2x}\text{, }&x\neq 0\\y\in \mathrm{R}\text{, }&z=1\text{ and }x=0\end{matrix}\right.
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2xy+1=z
Swap sides so that all variable terms are on the left hand side.
2xy=z-1
Subtract 1 from both sides.
2yx=z-1
The equation is in standard form.
\frac{2yx}{2y}=\frac{z-1}{2y}
Divide both sides by 2y.
x=\frac{z-1}{2y}
Dividing by 2y undoes the multiplication by 2y.
2xy+1=z
Swap sides so that all variable terms are on the left hand side.
2xy=z-1
Subtract 1 from both sides.
\frac{2xy}{2x}=\frac{z-1}{2x}
Divide both sides by 2x.
y=\frac{z-1}{2x}
Dividing by 2x undoes the multiplication by 2x.
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