Solve for z
z=\left(x+3\right)^{2}
Solve for x
x=-\left(\sqrt{z}+3\right)
x=\sqrt{z}-3\text{, }z\geq 0
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z=x^{2}+6x+9
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+3\right)^{2}.
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