Solve for x
x=\frac{\sqrt{2\left(\cos(z)+1\right)}}{2}
x=-\frac{\sqrt{2\left(\cos(z)+1\right)}}{2}\text{, }z\leq \pi \text{ and }z\geq 0\text{ and }\exists n_{1}\in \mathrm{Z}\text{ : }\left(z>\pi n_{1}+\frac{\pi }{2}\text{ and }z<\pi n_{1}+\frac{3\pi }{2}\right)
Solve for z
z=\arccos(2x^{2}-1)
|x|\neq \frac{\sqrt{2}}{2}\text{ and }|x|\leq 1
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