z = \frac { h } { H } e ^ { 1,4 \frac { y } { y } }
Solve for H
\left\{\begin{matrix}\\H\neq 0\text{, }&\text{unconditionally}\\H=\frac{e^{1,4}h}{z}\text{, }&h\neq 0\text{ and }z\neq 0\text{ and }y\neq 0\end{matrix}\right.
Solve for h
h=\frac{Hz}{e^{1,4}}
H\neq 0\text{ and }y\neq 0
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zH=he^{1,4\times \frac{y}{y}}
Variable H cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by H.
zH=he^{1,4\times 1}
Cancel out y in both numerator and denominator.
zH=he^{1,4}
Multiply 1,4 and 1 to get 1,4.
zH=e^{1,4}h
The equation is in standard form.
\frac{zH}{z}=\frac{e^{1,4}h}{z}
Divide both sides by z.
H=\frac{e^{1,4}h}{z}
Dividing by z undoes the multiplication by z.
H=\frac{e^{1,4}h}{z}\text{, }H\neq 0
Variable H cannot be equal to 0.
zH=he^{1,4\times \frac{y}{y}}
Multiply both sides of the equation by H.
zH=he^{1,4\times 1}
Cancel out y in both numerator and denominator.
zH=he^{1,4}
Multiply 1,4 and 1 to get 1,4.
he^{1,4}=zH
Swap sides so that all variable terms are on the left hand side.
e^{1,4}h=Hz
The equation is in standard form.
\frac{e^{1,4}h}{e^{1,4}}=\frac{Hz}{e^{1,4}}
Divide both sides by e^{1,4}.
h=\frac{Hz}{e^{1,4}}
Dividing by e^{1,4} undoes the multiplication by e^{1,4}.
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