Solve z=3*2^2/1-2+6*2^2/(1*2)-(4*2)

$$z = \frac { 3 \times 2 ^ { 2 } } { 1 - 2 } + \frac { 6 \times 2 ^ { 2 } } { ( 1 \times 2 ) - ( 4 \times 2 ) }$$

Solve for z

$$z=-16$$

Steps for Solving Linear Equation

Calculate 2 to the power of 2 and get 4.

$$z=\frac{3\times 4}{1-2}+\frac{6\times 2^{2}}{1\times 2-4\times 2}$$

Multiply 3 and 4 to get 12.

$$z=\frac{12}{1-2}+\frac{6\times 2^{2}}{1\times 2-4\times 2}$$

Subtract 2 from 1 to get -1.

$$z=\frac{12}{-1}+\frac{6\times 2^{2}}{1\times 2-4\times 2}$$

Fraction \frac{12}{-1} can be rewritten as -12 by extracting the negative sign.

$$z=-12+\frac{6\times 2^{2}}{1\times 2-4\times 2}$$

Calculate 2 to the power of 2 and get 4.

$$z=-12+\frac{6\times 4}{1\times 2-4\times 2}$$

Multiply 6 and 4 to get 24.

$$z=-12+\frac{24}{1\times 2-4\times 2}$$

Multiply 1 and 2 to get 2.

$$z=-12+\frac{24}{2-4\times 2}$$

Multiply 4 and 2 to get 8.

$$z=-12+\frac{24}{2-8}$$

Subtract 8 from 2 to get -6.

$$z=-12+\frac{24}{-6}$$

Divide 24 by -6 to get -4.

$$z=-12-4$$

Subtract 4 from -12 to get -16.

$$z=-16$$

Assign z

$$z≔-16$$