Solve z+1=-4/g

$$z + 1 = - \frac { 4 } { g }$$

Solve for g

$$g=-\frac{4}{z+1}$$

$$z\neq -1$$

Steps for Solving Linear Equation

Variable g cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by g.

$$gz+g=-4$$

Combine all terms containing g.

$$\left(z+1\right)g=-4$$

Divide both sides by z+1.

$$\frac{\left(z+1\right)g}{z+1}=-\frac{4}{z+1}$$

Dividing by z+1 undoes the multiplication by z+1.

$$g=-\frac{4}{z+1}$$

Variable g cannot be equal to 0.

$$g=-\frac{4}{z+1}\text{, }g\neq 0$$

Solve for z

$$z=-1-\frac{4}{g}$$

$$g\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by g.

$$gz+g=-4$$

Subtract g from both sides.

$$gz=-4-g$$

The equation is in standard form.

$$gz=-g-4$$

Divide both sides by g.

$$\frac{gz}{g}=\frac{-g-4}{g}$$

Dividing by g undoes the multiplication by g.

$$z=\frac{-g-4}{g}$$

Divide -4-g by g.

$$z=-1-\frac{4}{g}$$