Solve for x
x=2-3y
Solve for y
y=\frac{2-x}{3}
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y-0=\frac{1}{-1-2}\left(x-2\right)
Subtract 0 from 1 to get 1.
y-0=\frac{1}{-3}\left(x-2\right)
Subtract 2 from -1 to get -3.
y-0=-\frac{1}{3}\left(x-2\right)
Fraction \frac{1}{-3} can be rewritten as -\frac{1}{3} by extracting the negative sign.
y-0=-\frac{1}{3}x+\frac{2}{3}
Use the distributive property to multiply -\frac{1}{3} by x-2.
-\frac{1}{3}x+\frac{2}{3}=y-0
Swap sides so that all variable terms are on the left hand side.
-\frac{1}{3}x=y-0-\frac{2}{3}
Subtract \frac{2}{3} from both sides.
-\frac{1}{3}x=y-\frac{2}{3}
Reorder the terms.
\frac{-\frac{1}{3}x}{-\frac{1}{3}}=\frac{y-\frac{2}{3}}{-\frac{1}{3}}
Multiply both sides by -3.
x=\frac{y-\frac{2}{3}}{-\frac{1}{3}}
Dividing by -\frac{1}{3} undoes the multiplication by -\frac{1}{3}.
x=2-3y
Divide y-\frac{2}{3} by -\frac{1}{3} by multiplying y-\frac{2}{3} by the reciprocal of -\frac{1}{3}.
y-0=\frac{1}{-1-2}\left(x-2\right)
Subtract 0 from 1 to get 1.
y-0=\frac{1}{-3}\left(x-2\right)
Subtract 2 from -1 to get -3.
y-0=-\frac{1}{3}\left(x-2\right)
Fraction \frac{1}{-3} can be rewritten as -\frac{1}{3} by extracting the negative sign.
y-0=-\frac{1}{3}x+\frac{2}{3}
Use the distributive property to multiply -\frac{1}{3} by x-2.
y=-\frac{1}{3}x+\frac{2}{3}+0
Add 0 to both sides.
y=-\frac{1}{3}x+\frac{2}{3}
Add \frac{2}{3} and 0 to get \frac{2}{3}.
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Limits
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