Solve y-(-5)=1div2(x-3)

$$y-(-5)=1 \div 2(x-3)$$

Solve for x

$$x=2y+13$$

Steps for Solving Linear Equation

The opposite of -5 is 5.

$$y+5=\frac{1}{2}\left(x-3\right)$$

Use the distributive property to multiply \frac{1}{2} by x-3.

$$y+5=\frac{1}{2}x-\frac{3}{2}$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{1}{2}x-\frac{3}{2}=y+5$$

Add \frac{3}{2} to both sides.

$$\frac{1}{2}x=y+5+\frac{3}{2}$$

Add 5 and \frac{3}{2} to get \frac{13}{2}.

$$\frac{1}{2}x=y+\frac{13}{2}$$

Multiply both sides by 2.

$$\frac{\frac{1}{2}x}{\frac{1}{2}}=\frac{y+\frac{13}{2}}{\frac{1}{2}}$$

Dividing by \frac{1}{2} undoes the multiplication by \frac{1}{2}.

$$x=\frac{y+\frac{13}{2}}{\frac{1}{2}}$$

Divide y+\frac{13}{2} by \frac{1}{2} by multiplying y+\frac{13}{2} by the reciprocal of \frac{1}{2}.

$$x=2y+13$$

Solve for y

$$y=\frac{x-13}{2}$$

Solution Steps

The opposite of -5 is 5.

$$y+5=\frac{1}{2}\left(x-3\right)$$

Use the distributive property to multiply \frac{1}{2} by x-3.

$$y+5=\frac{1}{2}x-\frac{3}{2}$$

Subtract 5 from both sides.

$$y=\frac{1}{2}x-\frac{3}{2}-5$$

Subtract 5 from -\frac{3}{2} to get -\frac{13}{2}.

$$y=\frac{1}{2}x-\frac{13}{2}$$