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y=4x^{2}+5^{3}x^{3}-34\times \frac{48}{100}-56x
Expand \left(5x\right)^{3}.
y=4x^{2}+125x^{3}-34\times \frac{48}{100}-56x
Calculate 5 to the power of 3 and get 125.
y=4x^{2}+125x^{3}-34\times \frac{12}{25}-56x
Reduce the fraction \frac{48}{100} to lowest terms by extracting and canceling out 4.
y=4x^{2}+125x^{3}-\frac{408}{25}-56x
Multiply 34 and \frac{12}{25} to get \frac{408}{25}.