Solve y=2{left(3/2right)}^2+6{left(3/2right)}^2+10

$$y=2 { \left( \frac{ 3 }{ 2 } \right) }^{ 2 } +6 { \left( \frac{ 3 }{ 2 } \right) }^{ 2 } +10$$

Solve for y

$$y=28$$

Steps for Solving Linear Equation

Calculate \frac{3}{2} to the power of 2 and get \frac{9}{4}.

$$y=2\times \frac{9}{4}+6\times \left(\frac{3}{2}\right)^{2}+10$$

Express 2\times \frac{9}{4} as a single fraction.

$$y=\frac{2\times 9}{4}+6\times \left(\frac{3}{2}\right)^{2}+10$$

Multiply 2 and 9 to get 18.

$$y=\frac{18}{4}+6\times \left(\frac{3}{2}\right)^{2}+10$$

Reduce the fraction \frac{18}{4} to lowest terms by extracting and canceling out 2.

$$y=\frac{9}{2}+6\times \left(\frac{3}{2}\right)^{2}+10$$

Calculate \frac{3}{2} to the power of 2 and get \frac{9}{4}.

$$y=\frac{9}{2}+6\times \frac{9}{4}+10$$

Express 6\times \frac{9}{4} as a single fraction.

$$y=\frac{9}{2}+\frac{6\times 9}{4}+10$$

Multiply 6 and 9 to get 54.

$$y=\frac{9}{2}+\frac{54}{4}+10$$

Reduce the fraction \frac{54}{4} to lowest terms by extracting and canceling out 2.

$$y=\frac{9}{2}+\frac{27}{2}+10$$

Since \frac{9}{2} and \frac{27}{2} have the same denominator, add them by adding their numerators.

$$y=\frac{9+27}{2}+10$$

Add 9 and 27 to get 36.

$$y=\frac{36}{2}+10$$

Divide 36 by 2 to get 18.

$$y=18+10$$

Add 18 and 10 to get 28.

$$y=28$$

Assign y

$$y≔28$$