Solve y=-1+3/x+1

$$y=-1+ \frac{ 3 }{ x+1 }$$

Solve for x

$$x=-\frac{y-2}{y+1}$$

$$y\neq -1$$

Steps for Solving Linear Equation

Variable x cannot be equal to -1 since division by zero is not defined. Multiply both sides of the equation by x+1.

$$y\left(x+1\right)=\left(x+1\right)\left(-1\right)+3$$

Use the distributive property to multiply y by x+1.

$$yx+y=\left(x+1\right)\left(-1\right)+3$$

Use the distributive property to multiply x+1 by -1.

$$yx+y=-x-1+3$$

Add -1 and 3 to get 2.

$$yx+y=-x+2$$

Add x to both sides.

$$yx+y+x=2$$

Subtract y from both sides.

$$yx+x=2-y$$

Combine all terms containing x.

$$\left(y+1\right)x=2-y$$

Divide both sides by y+1.

$$\frac{\left(y+1\right)x}{y+1}=\frac{2-y}{y+1}$$

Dividing by y+1 undoes the multiplication by y+1.

$$x=\frac{2-y}{y+1}$$

Variable x cannot be equal to -1.

$$x=\frac{2-y}{y+1}\text{, }x\neq -1$$

Solve for y

$$y=-\frac{x-2}{x+1}$$

$$x\neq -1$$