Solve for x
x=\frac{4-4y}{3}
Solve for y
y=-\frac{3x}{4}+1
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-\frac{3}{4}x+1=y
Swap sides so that all variable terms are on the left hand side.
-\frac{3}{4}x=y-1
Subtract 1 from both sides.
\frac{-\frac{3}{4}x}{-\frac{3}{4}}=\frac{y-1}{-\frac{3}{4}}
Divide both sides of the equation by -\frac{3}{4}, which is the same as multiplying both sides by the reciprocal of the fraction.
x=\frac{y-1}{-\frac{3}{4}}
Dividing by -\frac{3}{4} undoes the multiplication by -\frac{3}{4}.
x=\frac{4-4y}{3}
Divide y-1 by -\frac{3}{4} by multiplying y-1 by the reciprocal of -\frac{3}{4}.
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