Solve y=(4-3x)div(1-2x)

$$y=(4-3x) \div (1-2x)$$

Solve for x

$$x=-\frac{y-4}{3-2y}$$

$$y\neq \frac{3}{2}$$

Steps for Solving Linear Equation

Variable x cannot be equal to \frac{1}{2} since division by zero is not defined. Multiply both sides of the equation by -2x+1.

$$y\left(-2x+1\right)=4-3x$$

Use the distributive property to multiply y by -2x+1.

$$-2yx+y=4-3x$$

Add 3x to both sides.

$$-2yx+y+3x=4$$

Subtract y from both sides.

$$-2yx+3x=4-y$$

Combine all terms containing x.

$$\left(-2y+3\right)x=4-y$$

The equation is in standard form.

$$\left(3-2y\right)x=4-y$$

Divide both sides by -2y+3.

$$\frac{\left(3-2y\right)x}{3-2y}=\frac{4-y}{3-2y}$$

Dividing by -2y+3 undoes the multiplication by -2y+3.

$$x=\frac{4-y}{3-2y}$$

Variable x cannot be equal to \frac{1}{2}.

$$x=\frac{4-y}{3-2y}\text{, }x\neq \frac{1}{2}$$

Solve for y

$$y=-\frac{3x-4}{1-2x}$$

$$x\neq \frac{1}{2}$$