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y=\frac{5+3}{5}x-1+2
Multiply 1 and 5 to get 5.
y=\frac{8}{5}x-1+2
Add 5 and 3 to get 8.
y=\frac{8}{5}x+1
Add -1 and 2 to get 1.
\frac{8}{5}x+1=y
Swap sides so that all variable terms are on the left hand side.
\frac{8}{5}x=y-1
Subtract 1 from both sides.
\frac{\frac{8}{5}x}{\frac{8}{5}}=\frac{y-1}{\frac{8}{5}}
Divide both sides of the equation by \frac{8}{5}, which is the same as multiplying both sides by the reciprocal of the fraction.
x=\frac{y-1}{\frac{8}{5}}
Dividing by \frac{8}{5} undoes the multiplication by \frac{8}{5}.
x=\frac{5y-5}{8}
Divide y-1 by \frac{8}{5} by multiplying y-1 by the reciprocal of \frac{8}{5}.
y=\frac{5+3}{5}x-1+2
Multiply 1 and 5 to get 5.
y=\frac{8}{5}x-1+2
Add 5 and 3 to get 8.
y=\frac{8}{5}x+1
Add -1 and 2 to get 1.