Solve y=5^2+5x^-1

$$y= { 5 }^{ 2 } +5 { x }^{ -1 }$$

Solve for x

$$x=-\frac{5}{25-y}$$

$$y\neq 25$$

Steps for Solving Linear Equation

Calculate 5 to the power of 2 and get 25.

$$y=25+5x^{-1}$$

Swap sides so that all variable terms are on the left hand side.

$$25+5x^{-1}=y$$

Reorder the terms.

$$25+5\times \frac{1}{x}=y$$

Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x.

$$x\times 25+5\times 1=yx$$

Multiply 5 and 1 to get 5.

$$x\times 25+5=yx$$

Subtract yx from both sides.

$$x\times 25+5-yx=0$$

Subtract 5 from both sides. Anything subtracted from zero gives its negation.

$$x\times 25-yx=-5$$

Combine all terms containing x.

$$\left(25-y\right)x=-5$$

Divide both sides by -y+25.

$$\frac{\left(25-y\right)x}{25-y}=-\frac{5}{25-y}$$

Dividing by -y+25 undoes the multiplication by -y+25.

$$x=-\frac{5}{25-y}$$

Variable x cannot be equal to 0.

$$x=-\frac{5}{25-y}\text{, }x\neq 0$$

Solve for y

$$y=25+\frac{5}{x}$$

$$x\neq 0$$