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y^{2}=\left(\sqrt{5y+6}\right)^{2}
Square both sides of the equation.
y^{2}=5y+6
Calculate \sqrt{5y+6} to the power of 2 and get 5y+6.
y^{2}-5y=6
Subtract 5y from both sides.
y^{2}-5y-6=0
Subtract 6 from both sides.
a+b=-5 ab=-6
To solve the equation, factor y^{2}-5y-6 using formula y^{2}+\left(a+b\right)y+ab=\left(y+a\right)\left(y+b\right). To find a and b, set up a system to be solved.
1,-6 2,-3
Since ab is negative, a and b have the opposite signs. Since a+b is negative, the negative number has greater absolute value than the positive. List all such integer pairs that give product -6.
1-6=-5 2-3=-1
Calculate the sum for each pair.
a=-6 b=1
The solution is the pair that gives sum -5.
\left(y-6\right)\left(y+1\right)
Rewrite factored expression \left(y+a\right)\left(y+b\right) using the obtained values.
y=6 y=-1
To find equation solutions, solve y-6=0 and y+1=0.
6=\sqrt{5\times 6+6}
Substitute 6 for y in the equation y=\sqrt{5y+6}.
6=6
Simplify. The value y=6 satisfies the equation.
-1=\sqrt{5\left(-1\right)+6}
Substitute -1 for y in the equation y=\sqrt{5y+6}.
-1=1
Simplify. The value y=-1 does not satisfy the equation because the left and the right hand side have opposite signs.
y=6
Equation y=\sqrt{5y+6} has a unique solution.