Solve y=x+z/2

$$y= \frac{ x+z }{ 2 }$$

Solve for x

$$x=2y-z$$

Steps for Solving Linear Equation

Divide each term of x+z by 2 to get \frac{1}{2}x+\frac{1}{2}z.

$$y=\frac{1}{2}x+\frac{1}{2}z$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{1}{2}x+\frac{1}{2}z=y$$

Subtract \frac{1}{2}z from both sides.

$$\frac{1}{2}x=y-\frac{1}{2}z$$

The equation is in standard form.

$$\frac{1}{2}x=-\frac{z}{2}+y$$

Multiply both sides by 2.

$$\frac{\frac{1}{2}x}{\frac{1}{2}}=\frac{-\frac{z}{2}+y}{\frac{1}{2}}$$

Dividing by \frac{1}{2} undoes the multiplication by \frac{1}{2}.

$$x=\frac{-\frac{z}{2}+y}{\frac{1}{2}}$$

Divide y-\frac{z}{2} by \frac{1}{2} by multiplying y-\frac{z}{2} by the reciprocal of \frac{1}{2}.

$$x=2y-z$$

Solve for y

$$y=\frac{x+z}{2}$$

Solution Steps

Divide each term of x+z by 2 to get \frac{1}{2}x+\frac{1}{2}z.

$$y=\frac{1}{2}x+\frac{1}{2}z$$