Solve y=8/x+3-2

$$y= \frac{ 8 }{ x+3 } -2$$

Solve for x

$$x=-\frac{3y-2}{y+2}$$

$$y\neq -2$$

Steps for Solving Linear Equation

Variable x cannot be equal to -3 since division by zero is not defined. Multiply both sides of the equation by x+3.

$$y\left(x+3\right)=8+\left(x+3\right)\left(-2\right)$$

Use the distributive property to multiply y by x+3.

$$yx+3y=8+\left(x+3\right)\left(-2\right)$$

Use the distributive property to multiply x+3 by -2.

$$yx+3y=8-2x-6$$

Subtract 6 from 8 to get 2.

$$yx+3y=2-2x$$

Add 2x to both sides.

$$yx+3y+2x=2$$

Subtract 3y from both sides.

$$yx+2x=2-3y$$

Combine all terms containing x.

$$\left(y+2\right)x=2-3y$$

Divide both sides by y+2.

$$\frac{\left(y+2\right)x}{y+2}=\frac{2-3y}{y+2}$$

Dividing by y+2 undoes the multiplication by y+2.

$$x=\frac{2-3y}{y+2}$$

Variable x cannot be equal to -3.

$$x=\frac{2-3y}{y+2}\text{, }x\neq -3$$

Solve for y

$$y=-\frac{2\left(x-1\right)}{x+3}$$

$$x\neq -3$$