Solve for x
x=\frac{5\left(y+3\right)}{2}
Solve for y
y=\frac{2x}{5}-3
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\frac{2}{5}x-3=y
Swap sides so that all variable terms are on the left hand side.
\frac{2}{5}x=y+3
Add 3 to both sides.
\frac{\frac{2}{5}x}{\frac{2}{5}}=\frac{y+3}{\frac{2}{5}}
Divide both sides of the equation by \frac{2}{5}, which is the same as multiplying both sides by the reciprocal of the fraction.
x=\frac{y+3}{\frac{2}{5}}
Dividing by \frac{2}{5} undoes the multiplication by \frac{2}{5}.
x=\frac{5y+15}{2}
Divide y+3 by \frac{2}{5} by multiplying y+3 by the reciprocal of \frac{2}{5}.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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