Solve y=13-4x/3

$$y= \frac{ 13-4x }{ 3 }$$

Solve for x

$$x=\frac{13-3y}{4}$$

Steps for Solving Linear Equation

Divide each term of 13-4x by 3 to get \frac{13}{3}-\frac{4}{3}x.

$$y=\frac{13}{3}-\frac{4}{3}x$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{13}{3}-\frac{4}{3}x=y$$

Subtract \frac{13}{3} from both sides.

$$-\frac{4}{3}x=y-\frac{13}{3}$$

Divide both sides of the equation by -\frac{4}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-\frac{4}{3}x}{-\frac{4}{3}}=\frac{y-\frac{13}{3}}{-\frac{4}{3}}$$

Dividing by -\frac{4}{3} undoes the multiplication by -\frac{4}{3}.

$$x=\frac{y-\frac{13}{3}}{-\frac{4}{3}}$$

Divide y-\frac{13}{3} by -\frac{4}{3} by multiplying y-\frac{13}{3} by the reciprocal of -\frac{4}{3}.

$$x=\frac{13-3y}{4}$$

Solve for y

$$y=\frac{13-4x}{3}$$

Solution Steps

Divide each term of 13-4x by 3 to get \frac{13}{3}-\frac{4}{3}x.

$$y=\frac{13}{3}-\frac{4}{3}x$$