Solve y=1-2x/3-x

$$y= \frac{ 1-2x }{ 3-x }$$

Solve for x

$$x=-\frac{3y-1}{2-y}$$

$$y\neq 2$$

Steps for Solving Linear Equation

Variable x cannot be equal to 3 since division by zero is not defined. Multiply both sides of the equation by -x+3.

$$y\left(-x+3\right)=1-2x$$

Use the distributive property to multiply y by -x+3.

$$-yx+3y=1-2x$$

Add 2x to both sides.

$$-yx+3y+2x=1$$

Subtract 3y from both sides.

$$-yx+2x=1-3y$$

Combine all terms containing x.

$$\left(-y+2\right)x=1-3y$$

The equation is in standard form.

$$\left(2-y\right)x=1-3y$$

Divide both sides by -y+2.

$$\frac{\left(2-y\right)x}{2-y}=\frac{1-3y}{2-y}$$

Dividing by -y+2 undoes the multiplication by -y+2.

$$x=\frac{1-3y}{2-y}$$

Variable x cannot be equal to 3.

$$x=\frac{1-3y}{2-y}\text{, }x\neq 3$$

Solve for y

$$y=-\frac{2x-1}{3-x}$$

$$x\neq 3$$