Solve y=1/23x+3

$$y= \frac{ 1 }{ 23x } +3$$

Solve for x

$$x=-\frac{1}{23\left(3-y\right)}$$

$$y\neq 3$$

Steps for Solving Linear Equation

Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 23x.

$$y\times 23x=1+23x\times 3$$

Multiply 23 and 3 to get 69.

$$y\times 23x=1+69x$$

Subtract 69x from both sides.

$$y\times 23x-69x=1$$

Combine all terms containing x.

$$\left(y\times 23-69\right)x=1$$

The equation is in standard form.

$$\left(23y-69\right)x=1$$

Divide both sides by 23y-69.

$$\frac{\left(23y-69\right)x}{23y-69}=\frac{1}{23y-69}$$

Dividing by 23y-69 undoes the multiplication by 23y-69.

$$x=\frac{1}{23y-69}$$

Divide 1 by 23y-69.

$$x=\frac{1}{23\left(y-3\right)}$$

Variable x cannot be equal to 0.

$$x=\frac{1}{23\left(y-3\right)}\text{, }x\neq 0$$

Solve for y

$$y=3+\frac{1}{23x}$$

$$x\neq 0$$