Solve y+4=(1/9)(x-6)

$$y+4=( \frac{ 1 }{ 9 } )(x-6)$$

Solve for x

$$x=9y+42$$

Steps for Solving Linear Equation

Use the distributive property to multiply \frac{1}{9} by x-6.

$$y+4=\frac{1}{9}x-\frac{2}{3}$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{1}{9}x-\frac{2}{3}=y+4$$

Add \frac{2}{3} to both sides.

$$\frac{1}{9}x=y+4+\frac{2}{3}$$

Add 4 and \frac{2}{3} to get \frac{14}{3}.

$$\frac{1}{9}x=y+\frac{14}{3}$$

Multiply both sides by 9.

$$\frac{\frac{1}{9}x}{\frac{1}{9}}=\frac{y+\frac{14}{3}}{\frac{1}{9}}$$

Dividing by \frac{1}{9} undoes the multiplication by \frac{1}{9}.

$$x=\frac{y+\frac{14}{3}}{\frac{1}{9}}$$

Divide y+\frac{14}{3} by \frac{1}{9} by multiplying y+\frac{14}{3} by the reciprocal of \frac{1}{9}.

$$x=9y+42$$

Solve for y

$$y=\frac{x-42}{9}$$

Solution Steps

Use the distributive property to multiply \frac{1}{9} by x-6.

$$y+4=\frac{1}{9}x-\frac{2}{3}$$

Subtract 4 from both sides.

$$y=\frac{1}{9}x-\frac{2}{3}-4$$

Subtract 4 from -\frac{2}{3} to get -\frac{14}{3}.

$$y=\frac{1}{9}x-\frac{14}{3}$$