Solve y+3=-3/4(x-1)

$$y+3=- \frac{ 3 }{ 4 } (x-1)$$

Solve for x

$$x=-\frac{4y}{3}-3$$

Steps for Solving Linear Equation

Use the distributive property to multiply -\frac{3}{4} by x-1.

$$y+3=-\frac{3}{4}x+\frac{3}{4}$$

Swap sides so that all variable terms are on the left hand side.

$$-\frac{3}{4}x+\frac{3}{4}=y+3$$

Subtract \frac{3}{4} from both sides.

$$-\frac{3}{4}x=y+3-\frac{3}{4}$$

Subtract \frac{3}{4} from 3 to get \frac{9}{4}.

$$-\frac{3}{4}x=y+\frac{9}{4}$$

Divide both sides of the equation by -\frac{3}{4}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-\frac{3}{4}x}{-\frac{3}{4}}=\frac{y+\frac{9}{4}}{-\frac{3}{4}}$$

Dividing by -\frac{3}{4} undoes the multiplication by -\frac{3}{4}.

$$x=\frac{y+\frac{9}{4}}{-\frac{3}{4}}$$

Divide y+\frac{9}{4} by -\frac{3}{4} by multiplying y+\frac{9}{4} by the reciprocal of -\frac{3}{4}.

$$x=-\frac{4y}{3}-3$$

Solve for y

$$y=\frac{-3x-9}{4}$$

Solution Steps

Use the distributive property to multiply -\frac{3}{4} by x-1.

$$y+3=-\frac{3}{4}x+\frac{3}{4}$$

Subtract 3 from both sides.

$$y=-\frac{3}{4}x+\frac{3}{4}-3$$

Subtract 3 from \frac{3}{4} to get -\frac{9}{4}.

$$y=-\frac{3}{4}x-\frac{9}{4}$$