Solve y_a^2+24x+16=0

$$y _ { a } ^ { 2 } + 24 x + 16 = 0$$

Solve for x

$$x=-\frac{y_{a}^{2}}{24}-\frac{2}{3}$$

Steps for Solving Linear Equation

Subtract y_{a}^{2} from both sides. Anything subtracted from zero gives its negation.

$$24x+16=-y_{a}^{2}$$

Subtract 16 from both sides.

$$24x=-y_{a}^{2}-16$$

Divide both sides by 24.

$$\frac{24x}{24}=\frac{-y_{a}^{2}-16}{24}$$

Dividing by 24 undoes the multiplication by 24.

$$x=\frac{-y_{a}^{2}-16}{24}$$

Divide -y_{a}^{2}-16 by 24.

$$x=-\frac{y_{a}^{2}}{24}-\frac{2}{3}$$

Solve for y_a (complex solution)

$$y_{a}=-2\sqrt{-6x-4}$$

$$y_{a}=2\sqrt{-6x-4}$$

Solve for y_a

$$y_{a}=2\sqrt{-6x-4}$$

$$y_{a}=-2\sqrt{-6x-4}\text{, }x\leq -\frac{2}{3}$$