Solve for x
x=48-3y_{1}
Solve for y_1
y_{1}=-\frac{x}{3}+16
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-\frac{1}{3}x+16=y_{1}
Swap sides so that all variable terms are on the left hand side.
-\frac{1}{3}x=y_{1}-16
Subtract 16 from both sides.
\frac{-\frac{1}{3}x}{-\frac{1}{3}}=\frac{y_{1}-16}{-\frac{1}{3}}
Multiply both sides by -3.
x=\frac{y_{1}-16}{-\frac{1}{3}}
Dividing by -\frac{1}{3} undoes the multiplication by -\frac{1}{3}.
x=48-3y_{1}
Divide y_{1}-16 by -\frac{1}{3} by multiplying y_{1}-16 by the reciprocal of -\frac{1}{3}.
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