Solve y_{1}=2/3x+1

$$y _ { 1 } = \frac { 2 } { 3 } x + 1$$

Solve for x

$$x=\frac{3\left(y_{1}-1\right)}{2}$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$\frac{2}{3}x+1=y_{1}$$

Subtract 1 from both sides.

$$\frac{2}{3}x=y_{1}-1$$

Divide both sides of the equation by \frac{2}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{2}{3}x}{\frac{2}{3}}=\frac{y_{1}-1}{\frac{2}{3}}$$

Dividing by \frac{2}{3} undoes the multiplication by \frac{2}{3}.

$$x=\frac{y_{1}-1}{\frac{2}{3}}$$

Divide y_{1}-1 by \frac{2}{3} by multiplying y_{1}-1 by the reciprocal of \frac{2}{3}.

$$x=\frac{3y_{1}-3}{2}$$

Solve for y_1

$$y_{1}=\frac{2x}{3}+1$$