Solve y_{1}+y_{2}=-6m/3m^2+4quady_{1}y=-9/3m^2+4

$$y _ { 1 } + y _ { 2 } = \frac { - 6 m } { 3 m ^ { 2 } + 4 } \quad y _ { 1 } y = \frac { - 9 } { 3 m ^ { 2 } + 4 }$$

Evaluate (complex solution)

$$y_{1}+y_{2}=-\frac{6myy_{1}}{3m^{2}+4}\text{ and }-\frac{6myy_{1}}{3m^{2}+4}=-\frac{9}{3m^{2}+4}$$

Solve for y

$$y=-\frac{\left(y_{1}+y_{2}\right)\left(3m^{2}+4\right)}{6my_{1}}$$

$$m\neq 0\text{ and }y_{1}<-y_{2}\text{ and }y_{1}\neq 0\text{ and }|m|=\frac{\sqrt{12y_{1}+12y_{2}+27}}{3\sqrt{-\left(y_{1}+y_{2}\right)}}\text{ and }y_{1}>-y_{2}-\frac{9}{4}$$

Solve for y_2

$$y_{2}=-\frac{3\left(6my+3m^{2}+4\right)}{2my\left(3m^{2}+4\right)}$$

$$m\neq 0\text{ and }y_{1}\neq 0\text{ and }y=\frac{3}{2my_{1}}$$