Solve y-t=-sqrt{(}quad-s)

$$y - t = - \sqrt { ( } \quad - s )$$

Solve for s

$$s=-\left(y-t\right)^{2}$$

$$-\left(y-t\right)\geq 0$$

Steps for Solving Radical Equations

Swap sides so that all variable terms are on the left hand side.

$$-\sqrt{-s}=y-t$$

Divide both sides by -1.

$$\frac{-\sqrt{-s}}{-1}=\frac{y-t}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$\sqrt{-s}=\frac{y-t}{-1}$$

Divide y-t by -1.

$$\sqrt{-s}=t-y$$

Square both sides of the equation.

$$-s=\left(t-y\right)^{2}$$

Divide both sides by -1.

$$\frac{-s}{-1}=\frac{\left(t-y\right)^{2}}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$s=\frac{\left(t-y\right)^{2}}{-1}$$

Divide \left(-y+t\right)^{2} by -1.

$$s=-\left(t-y\right)^{2}$$

Solve for t

$$t=y+\sqrt{-s}$$

$$s\leq 0$$

Steps for Solving Linear Equation

Subtract y from both sides.

$$-t=-\sqrt{-s}-y$$

The equation is in standard form.

$$-t=-y-\sqrt{-s}$$

Divide both sides by -1.

$$\frac{-t}{-1}=\frac{-y-\sqrt{-s}}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$t=\frac{-y-\sqrt{-s}}{-1}$$

Divide -\sqrt{-s}-y by -1.

$$t=y+\sqrt{-s}$$