Solve y-7=-4/3(x+1)

$$y - 7 = - \frac { 4 } { 3 } ( x + 1 )$$

Solve for x

$$x=\frac{17-3y}{4}$$

Steps for Solving Linear Equation

Use the distributive property to multiply -\frac{4}{3} by x+1.

$$y-7=-\frac{4}{3}x-\frac{4}{3}$$

Swap sides so that all variable terms are on the left hand side.

$$-\frac{4}{3}x-\frac{4}{3}=y-7$$

Add \frac{4}{3} to both sides.

$$-\frac{4}{3}x=y-7+\frac{4}{3}$$

Add -7 and \frac{4}{3} to get -\frac{17}{3}.

$$-\frac{4}{3}x=y-\frac{17}{3}$$

Divide both sides of the equation by -\frac{4}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-\frac{4}{3}x}{-\frac{4}{3}}=\frac{y-\frac{17}{3}}{-\frac{4}{3}}$$

Dividing by -\frac{4}{3} undoes the multiplication by -\frac{4}{3}.

$$x=\frac{y-\frac{17}{3}}{-\frac{4}{3}}$$

Divide y-\frac{17}{3} by -\frac{4}{3} by multiplying y-\frac{17}{3} by the reciprocal of -\frac{4}{3}.

$$x=\frac{17-3y}{4}$$

Solve for y

$$y=\frac{17-4x}{3}$$

Solution Steps

Use the distributive property to multiply -\frac{4}{3} by x+1.

$$y-7=-\frac{4}{3}x-\frac{4}{3}$$

Add 7 to both sides.

$$y=-\frac{4}{3}x-\frac{4}{3}+7$$

Add -\frac{4}{3} and 7 to get \frac{17}{3}.

$$y=-\frac{4}{3}x+\frac{17}{3}$$