Solve for y
y=e^{\frac{4}{x}}+\frac{4}{x}
x\neq 0
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xy-4=xe^{\frac{4}{x}}
Multiply both sides of the equation by x.
xy=xe^{\frac{4}{x}}+4
Add 4 to both sides.
\frac{xy}{x}=\frac{xe^{\frac{4}{x}}+4}{x}
Divide both sides by x.
y=\frac{xe^{\frac{4}{x}}+4}{x}
Dividing by x undoes the multiplication by x.
y=e^{\frac{4}{x}}+\frac{4}{x}
Divide xe^{\frac{4}{x}}+4 by x.
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