Solve for x
x=\frac{y+19}{3}
Solve for y
y=3x-19
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-3x=-19-y
Subtract y from both sides.
-3x=-y-19
The equation is in standard form.
\frac{-3x}{-3}=\frac{-y-19}{-3}
Divide both sides by -3.
x=\frac{-y-19}{-3}
Dividing by -3 undoes the multiplication by -3.
x=\frac{y+19}{3}
Divide -19-y by -3.
y=-19+3x
Add 3x to both sides.
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