Solve y-3-3+(-3)-(-4)

$$y - 3 - 3 + ( - 3 ) - ( - 4 )$$

Evaluate

$$y-5$$

Solution Steps

Subtract 3 from -3 to get -6.

$$y-6-3-\left(-4\right)$$

Subtract 3 from -6 to get -9.

$$y-9-\left(-4\right)$$

The opposite of -4 is 4.

$$y-9+4$$

Add -9 and 4 to get -5.

$$y-5$$

Differentiate w.r.t. y

$$1$$

Steps Using Derivative Rule for Sum

Subtract 3 from -3 to get -6.

$$\frac{\mathrm{d}}{\mathrm{d}y}(y-6-3-\left(-4\right))$$

Subtract 3 from -6 to get -9.

$$\frac{\mathrm{d}}{\mathrm{d}y}(y-9-\left(-4\right))$$

The opposite of -4 is 4.

$$\frac{\mathrm{d}}{\mathrm{d}y}(y-9+4)$$

Add -9 and 4 to get -5.

$$\frac{\mathrm{d}}{\mathrm{d}y}(y-5)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$y^{1-1}$$

Subtract 1 from 1.

$$y^{0}$$

For any term t except 0, t^{0}=1.

$$1$$