Solve y-3div1/3+1=

$$y - 3 \div \frac { 1 } { 3 } + 1 =$$

Evaluate

$$y-8$$

Solution Steps

Divide 3 by \frac{1}{3} by multiplying 3 by the reciprocal of \frac{1}{3}.

$$y-3\times 3+1$$

Multiply 3 and 3 to get 9.

$$y-9+1$$

Add -9 and 1 to get -8.

$$y-8$$

Differentiate w.r.t. y

$$1$$

Steps Using Derivative Rule for Sum

Divide 3 by \frac{1}{3} by multiplying 3 by the reciprocal of \frac{1}{3}.

$$\frac{\mathrm{d}}{\mathrm{d}y}(y-3\times 3+1)$$

Multiply 3 and 3 to get 9.

$$\frac{\mathrm{d}}{\mathrm{d}y}(y-9+1)$$

Add -9 and 1 to get -8.

$$\frac{\mathrm{d}}{\mathrm{d}y}(y-8)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$y^{1-1}$$

Subtract 1 from 1.

$$y^{0}$$

For any term t except 0, t^{0}=1.

$$1$$