Solve y-3=-1/4(x-1)

$$y - 3 = - \frac { 1 } { 4 } ( x - 1 )$$

Solve for x

$$x=13-4y$$

Steps for Solving Linear Equation

Use the distributive property to multiply -\frac{1}{4} by x-1.

$$y-3=-\frac{1}{4}x+\frac{1}{4}$$

Swap sides so that all variable terms are on the left hand side.

$$-\frac{1}{4}x+\frac{1}{4}=y-3$$

Subtract \frac{1}{4} from both sides.

$$-\frac{1}{4}x=y-3-\frac{1}{4}$$

Subtract \frac{1}{4} from -3 to get -\frac{13}{4}.

$$-\frac{1}{4}x=y-\frac{13}{4}$$

Multiply both sides by -4.

$$\frac{-\frac{1}{4}x}{-\frac{1}{4}}=\frac{y-\frac{13}{4}}{-\frac{1}{4}}$$

Dividing by -\frac{1}{4} undoes the multiplication by -\frac{1}{4}.

$$x=\frac{y-\frac{13}{4}}{-\frac{1}{4}}$$

Divide y-\frac{13}{4} by -\frac{1}{4} by multiplying y-\frac{13}{4} by the reciprocal of -\frac{1}{4}.

$$x=13-4y$$

Solve for y

$$y=\frac{13-x}{4}$$

Solution Steps

Use the distributive property to multiply -\frac{1}{4} by x-1.

$$y-3=-\frac{1}{4}x+\frac{1}{4}$$

Add 3 to both sides.

$$y=-\frac{1}{4}x+\frac{1}{4}+3$$

Add \frac{1}{4} and 3 to get \frac{13}{4}.

$$y=-\frac{1}{4}x+\frac{13}{4}$$