Solve y-3=-1/2f(2x-4)

$$y - 3 = - \frac { 1 } { 2 } f ( 2 x - 4 )$$

Solve for f (complex solution)

$$\left\{\begin{matrix}f=-\frac{y-3}{x-2}\text{, }&x\neq 2\\f\in \mathrm{C}\text{, }&y=3\text{ and }x=2\end{matrix}\right.$$

Steps for Solving Linear Equation

Use the distributive property to multiply -\frac{1}{2}f by 2x-4.

$$y-3=-fx+2f$$

Swap sides so that all variable terms are on the left hand side.

$$-fx+2f=y-3$$

Combine all terms containing f.

$$\left(-x+2\right)f=y-3$$

The equation is in standard form.

$$\left(2-x\right)f=y-3$$

Divide both sides by 2-x.

$$\frac{\left(2-x\right)f}{2-x}=\frac{y-3}{2-x}$$

Dividing by 2-x undoes the multiplication by 2-x.

$$f=\frac{y-3}{2-x}$$

Solve for x (complex solution)

$$\left\{\begin{matrix}x=\frac{3+2f-y}{f}\text{, }&f\neq 0\\x\in \mathrm{C}\text{, }&y=3\text{ and }f=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Use the distributive property to multiply -\frac{1}{2}f by 2x-4.

$$y-3=-fx+2f$$

Swap sides so that all variable terms are on the left hand side.

$$-fx+2f=y-3$$

Subtract 2f from both sides.

$$-fx=y-3-2f$$

The equation is in standard form.

$$\left(-f\right)x=y-2f-3$$

Divide both sides by -f.

$$\frac{\left(-f\right)x}{-f}=\frac{y-2f-3}{-f}$$

Dividing by -f undoes the multiplication by -f.

$$x=\frac{y-2f-3}{-f}$$

Divide y-2f-3 by -f.

$$x=-\frac{y-2f-3}{f}$$

Solve for f

$$\left\{\begin{matrix}f=-\frac{y-3}{x-2}\text{, }&x\neq 2\\f\in \mathrm{R}\text{, }&y=3\text{ and }x=2\end{matrix}\right.$$

Steps for Solving Linear Equation

Use the distributive property to multiply -\frac{1}{2}f by 2x-4.

$$y-3=-fx+2f$$

Swap sides so that all variable terms are on the left hand side.

$$-fx+2f=y-3$$

Combine all terms containing f.

$$\left(-x+2\right)f=y-3$$

The equation is in standard form.

$$\left(2-x\right)f=y-3$$

Divide both sides by 2-x.

$$\frac{\left(2-x\right)f}{2-x}=\frac{y-3}{2-x}$$

Dividing by 2-x undoes the multiplication by 2-x.

$$f=\frac{y-3}{2-x}$$

Solve for x

$$\left\{\begin{matrix}x=\frac{3+2f-y}{f}\text{, }&f\neq 0\\x\in \mathrm{R}\text{, }&y=3\text{ and }f=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Use the distributive property to multiply -\frac{1}{2}f by 2x-4.

$$y-3=-fx+2f$$

Swap sides so that all variable terms are on the left hand side.

$$-fx+2f=y-3$$

Subtract 2f from both sides.

$$-fx=y-3-2f$$

The equation is in standard form.

$$\left(-f\right)x=y-2f-3$$

Divide both sides by -f.

$$\frac{\left(-f\right)x}{-f}=\frac{y-2f-3}{-f}$$

Dividing by -f undoes the multiplication by -f.

$$x=\frac{y-2f-3}{-f}$$

Divide y-2f-3 by -f.

$$x=-\frac{y-2f-3}{f}$$