Solve for y
y=\left(x+1\right)^{2}+3
Solve for x (complex solution)
x=-\left(\sqrt{y-3}+1\right)
x=\sqrt{y-3}-1
Solve for x
x=-\left(\sqrt{y-3}+1\right)
x=\sqrt{y-3}-1\text{, }y\geq 3
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y-3=x^{2}+2x+1
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+1\right)^{2}.
y=x^{2}+2x+1+3
Add 3 to both sides.
y=x^{2}+2x+4
Add 1 and 3 to get 4.
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