Solve y-3=7/8(x-4)

$$y - 3 = \frac { 7 } { 8 } ( x - 4 )$$

Solve for x

$$x=\frac{8y+4}{7}$$

Steps for Solving Linear Equation

Use the distributive property to multiply \frac{7}{8} by x-4.

$$y-3=\frac{7}{8}x-\frac{7}{2}$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{7}{8}x-\frac{7}{2}=y-3$$

Add \frac{7}{2} to both sides.

$$\frac{7}{8}x=y-3+\frac{7}{2}$$

Add -3 and \frac{7}{2} to get \frac{1}{2}.

$$\frac{7}{8}x=y+\frac{1}{2}$$

Divide both sides of the equation by \frac{7}{8}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{7}{8}x}{\frac{7}{8}}=\frac{y+\frac{1}{2}}{\frac{7}{8}}$$

Dividing by \frac{7}{8} undoes the multiplication by \frac{7}{8}.

$$x=\frac{y+\frac{1}{2}}{\frac{7}{8}}$$

Divide y+\frac{1}{2} by \frac{7}{8} by multiplying y+\frac{1}{2} by the reciprocal of \frac{7}{8}.

$$x=\frac{8y+4}{7}$$

Solve for y

$$y=\frac{7x}{8}-\frac{1}{2}$$

Solution Steps

Use the distributive property to multiply \frac{7}{8} by x-4.

$$y-3=\frac{7}{8}x-\frac{7}{2}$$

Add 3 to both sides.

$$y=\frac{7}{8}x-\frac{7}{2}+3$$

Add -\frac{7}{2} and 3 to get -\frac{1}{2}.

$$y=\frac{7}{8}x-\frac{1}{2}$$