Solve y-3=5/3(x+2)

$$y - 3 = \frac { 5 } { 3 } ( x + 2 )$$

Solve for x

$$x=\frac{3y-19}{5}$$

Steps for Solving Linear Equation

Use the distributive property to multiply \frac{5}{3} by x+2.

$$y-3=\frac{5}{3}x+\frac{10}{3}$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{5}{3}x+\frac{10}{3}=y-3$$

Subtract \frac{10}{3} from both sides.

$$\frac{5}{3}x=y-3-\frac{10}{3}$$

Subtract \frac{10}{3} from -3 to get -\frac{19}{3}.

$$\frac{5}{3}x=y-\frac{19}{3}$$

Divide both sides of the equation by \frac{5}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{5}{3}x}{\frac{5}{3}}=\frac{y-\frac{19}{3}}{\frac{5}{3}}$$

Dividing by \frac{5}{3} undoes the multiplication by \frac{5}{3}.

$$x=\frac{y-\frac{19}{3}}{\frac{5}{3}}$$

Divide y-\frac{19}{3} by \frac{5}{3} by multiplying y-\frac{19}{3} by the reciprocal of \frac{5}{3}.

$$x=\frac{3y-19}{5}$$

Solve for y

$$y=\frac{5x+19}{3}$$

Solution Steps

Use the distributive property to multiply \frac{5}{3} by x+2.

$$y-3=\frac{5}{3}x+\frac{10}{3}$$

Add 3 to both sides.

$$y=\frac{5}{3}x+\frac{10}{3}+3$$

Add \frac{10}{3} and 3 to get \frac{19}{3}.

$$y=\frac{5}{3}x+\frac{19}{3}$$