Solve y-3=4/3(x-4)

$$y - 3 = \frac { 4 } { 3 } ( x - 4 )$$

Solve for x

$$x=\frac{3y+7}{4}$$

Steps for Solving Linear Equation

Use the distributive property to multiply \frac{4}{3} by x-4.

$$y-3=\frac{4}{3}x-\frac{16}{3}$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{4}{3}x-\frac{16}{3}=y-3$$

Add \frac{16}{3} to both sides.

$$\frac{4}{3}x=y-3+\frac{16}{3}$$

Add -3 and \frac{16}{3} to get \frac{7}{3}.

$$\frac{4}{3}x=y+\frac{7}{3}$$

Divide both sides of the equation by \frac{4}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{4}{3}x}{\frac{4}{3}}=\frac{y+\frac{7}{3}}{\frac{4}{3}}$$

Dividing by \frac{4}{3} undoes the multiplication by \frac{4}{3}.

$$x=\frac{y+\frac{7}{3}}{\frac{4}{3}}$$

Divide y+\frac{7}{3} by \frac{4}{3} by multiplying y+\frac{7}{3} by the reciprocal of \frac{4}{3}.

$$x=\frac{3y+7}{4}$$

Solve for y

$$y=\frac{4x-7}{3}$$

Solution Steps

Use the distributive property to multiply \frac{4}{3} by x-4.

$$y-3=\frac{4}{3}x-\frac{16}{3}$$

Add 3 to both sides.

$$y=\frac{4}{3}x-\frac{16}{3}+3$$

Add -\frac{16}{3} and 3 to get -\frac{7}{3}.

$$y=\frac{4}{3}x-\frac{7}{3}$$