Solve y-2=7/4(x+1)

$$y - 2 = \frac { 7 } { 4 } ( x + 1 )$$

Solve for x

$$x=\frac{4y-15}{7}$$

Steps for Solving Linear Equation

Use the distributive property to multiply \frac{7}{4} by x+1.

$$y-2=\frac{7}{4}x+\frac{7}{4}$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{7}{4}x+\frac{7}{4}=y-2$$

Subtract \frac{7}{4} from both sides.

$$\frac{7}{4}x=y-2-\frac{7}{4}$$

Subtract \frac{7}{4} from -2 to get -\frac{15}{4}.

$$\frac{7}{4}x=y-\frac{15}{4}$$

Divide both sides of the equation by \frac{7}{4}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{7}{4}x}{\frac{7}{4}}=\frac{y-\frac{15}{4}}{\frac{7}{4}}$$

Dividing by \frac{7}{4} undoes the multiplication by \frac{7}{4}.

$$x=\frac{y-\frac{15}{4}}{\frac{7}{4}}$$

Divide y-\frac{15}{4} by \frac{7}{4} by multiplying y-\frac{15}{4} by the reciprocal of \frac{7}{4}.

$$x=\frac{4y-15}{7}$$

Solve for y

$$y=\frac{7x+15}{4}$$

Solution Steps

Use the distributive property to multiply \frac{7}{4} by x+1.

$$y-2=\frac{7}{4}x+\frac{7}{4}$$

Add 2 to both sides.

$$y=\frac{7}{4}x+\frac{7}{4}+2$$

Add \frac{7}{4} and 2 to get \frac{15}{4}.

$$y=\frac{7}{4}x+\frac{15}{4}$$