Solve for y
y=2\left(x-3\right)^{2}+1
Solve for x (complex solution)
x=-\frac{\sqrt{2y-2}}{2}+3
x=\frac{\sqrt{2y-2}}{2}+3
Solve for x
x=-\frac{\sqrt{2y-2}}{2}+3
x=\frac{\sqrt{2y-2}}{2}+3\text{, }y\geq 1
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y-1=2\left(x^{2}-6x+9\right)
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-3\right)^{2}.
y-1=2x^{2}-12x+18
Use the distributive property to multiply 2 by x^{2}-6x+9.
y=2x^{2}-12x+18+1
Add 1 to both sides.
y=2x^{2}-12x+19
Add 18 and 1 to get 19.
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